Redox Reactions And Electrochemistry Ques 285
Question: How many atoms of calcium will be deposited from a solution of $ CaCl_2 $ by a current of 25 milliamperes flowing for 60 seconds [BHU 1999]
Options:
A) $ 4.68\times 10^{18} $
B) $ 4.68\times 10^{15} $
C) $ 4.68\times 10^{12} $
D) $ 4.68\times 10^{9} $
Show Answer
Answer:
Correct Answer: A
Solution:
Quantity of electricity passed = $ \frac{25}{1000}\times 60=1.5 $
$ 2F=2\times 96500,C $ deposit $ Ca=1mole $ \ 1.5 C will deposit $ Ca=\frac{1}{2\times 96500}\times 1.5,mole $
$ =\frac{1}{2\times 96500}\times 1.5\times 6.023\times 10^{23} $ atom $ =4.68\times 10^{18} $ .
