SATHEE: Redox Reactions And Electrochemistry Ques 223

Redox Reactions And Electrochemistry Ques 223

Question: $C r_{2} O_{7}^{2 -} + I^{-} \to I_{2} + C r^{3 +}$ $E_{c e l l}^{0} = 0.79 V$ $E_{C r_{2} O_{7}^{2 -}}^{0} = 1.33 V, E_{I_{2}}^{0}$ is [BVP 2004]

Options:

A) $- 0.10 V$

B) $+ 0.18 V$

C) $- 0.54 V$

D) $0.54 V$

Show Answer

Answer:

Correct Answer: D

Solution:

$I^{-}$ get oxidised to $I_{2}$ hence will form anode and $C r_{2} O_{7}^{2 -}$ get reduced to $C r^{3 +}$ hence will form cathode.

$E_{c e l l}^{0} = E_{C a t h o d e}^{0} - E_{A n o d e}^{0}$ ;

$E_{C e l l^{0}} = E_{C r_{2} O_{7}^{- 2}}^{} - E_{I_{2}^{0}}$

$0.79 = 1.33 - E_{I_{2}^{0}}$ ; $E_{I_{2}^{0}} = 1.33 - 0.79$ ; $E_{I_{2}^{0}} = 0.54 V$ .

पिछला

अगला

गोपनीयता नीति

द्वारा संचालित Prutor@IITK

sathee@iitk.ac.in

SATHEE का मीडिया कवरेज

खेल स्टोर

ऐप स्टोर

Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on "I understand".

Redox Reactions And Electrochemistry Ques 223

Question: Cr2O72−+I−→I2+Cr3+ Ecell0=0.79 V ECr2O72−0=1.33 V, EI20 is [BVP 2004]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question: $C r_{2} O_{7}^{2 -} + I^{-} \to I_{2} + C r^{3 +}$ $E_{c e l l}^{0} = 0.79 V$ $E_{C r_{2} O_{7}^{2 -}}^{0} = 1.33 V, E_{I_{2}}^{0}$ is [BVP 2004]