SATHEE: Redox Reactions And Electrochemistry Ques 222

Redox Reactions And Electrochemistry Ques 222

Question: Consider the following $E^{0}$ values : $E_{F e^{3 +} / F e^{2 +}}^{0}$ = $+ 0.77 V$ $E_{S n^{2 +} / S n}^{0} = - 0.14 V$ Under standard conditions the potential for the reaction $S n_{(s)} + 2 F e^{3 +} (a q) \to 2 F e^{2 +} (s q) + S n^{2 +} (a q)$ is [AIEEE 2004]

Options:

A) 0.91 V

B) 1.40 V

C) 1.68 V

D) 0.63 V

Show Answer

Answer:

Correct Answer: A

Solution:

For $S n_{(s)} + 2 F e_{(a q)}^{3 +} \to 2 F e_{(a q)}^{2 +} + S n_{(a q)}^{2 +}$ $E_{c e l l}^{0} = E_{S n / S n^{2 +}}^{0} + E_{F e^{3 +} / F e^{2 +}}^{0}$ $= (0.14) + (0.77)$ $E_{c e l l}^{} = 0.91 V o l t s$ .

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Redox Reactions And Electrochemistry Ques 222

Question: Consider the following E0 values : EFe3+/Fe2+0 = +0.77 V ESn2+/Sn0=−0.14 V Under standard conditions the potential for the reaction Sn(s)+2Fe3+(aq)→2Fe2+(sq)+Sn2+(aq) is [AIEEE 2004]

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Question: Consider the following $E^{0}$ values : $E_{F e^{3 +} / F e^{2 +}}^{0}$ = $+ 0.77 V$ $E_{S n^{2 +} / S n}^{0} = - 0.14 V$ Under standard conditions the potential for the reaction $S n_{(s)} + 2 F e^{3 +} (a q) \to 2 F e^{2 +} (s q) + S n^{2 +} (a q)$ is [AIEEE 2004]