Redox Reactions And Electrochemistry Ques 222
Question: Consider the following $ E^{0} $ values : $ E^0_{F{e^{3+}}/F{e^{2+}}} $ = $ +0.77\ V $ $ E^0_{S{n^{2+}}/Sn}=-0.14\ V $ Under standard conditions the potential for the reaction $ S{n_{(s)}}+2F{e^{3+}}(aq)\to 2F{e^{2+}}(sq)+S{n^{2+}}(aq) $ is [AIEEE 2004]
Options:
A) 0.91 V
B) 1.40 V
C) 1.68 V
D) 0.63 V
Show Answer
Answer:
Correct Answer: A
Solution:
For $ S{n_{(s)}}+2Fe_{(aq)}^{3+}\to 2Fe_{(aq)}^{2+}+Sn_{(aq)}^{2+} $ $ E_{cell}^{0}=E_{Sn/S{n^{2+}}}^{0}+E_{F{e^{3+}}/F{e^{2+}}}^{0} $ $ =(0.14)+(0.77) $ $ E_{cell}^{{}}=0.91\ Volts $ .
