Redox Reactions And Electrochemistry Ques 219
Question: The e.m.f. of the cell $ Ag|A{g^{+}}(0.1M)||A{g^{+}}(1M)|Ag $ at 298 K is [DCE 2003]
Options:
A) 0.0059 V
B) 0.059 V
C) 5.9 V
D) 0.59 V
Show Answer
Answer:
Correct Answer: B
Solution:
$ Ag|A{g^{+}}(.1m)||A{g^{+}}1M|Ag| $ $ E_{Cell}=\frac{2.303RT}{nF}\log \frac{c_1}{c_2}=\frac{0.059}{1}\log \frac{1}{0.1} $ $ =0.059\log 10=0.059\ Volt $ .
