Redox Reactions And Electrochemistry Ques 217

Question: For the cell reaction, $ 2C{e^{4+}}+Co\to 2C{e^{3+}}+C{o^{2+}} $ $ E{{{}^\circ } _{cell}} $ is 1.89 V. If $ E{{{}^\circ } _{C{e^{4+}}/C{e^{3+}}}} $ [Pb.CET 2000]

Options:

A) - 1.64 V

B) + 1.64 V

C) - 2.08 V

D) + 2.17 V

Show Answer

Answer:

Correct Answer: B

Solution:

In this cell Co is oxidised and it acts as anode and Ce acts as cathode. $ E_{cell}^{0}=E_{Cathode}^{0}-E_{Anode}^{0} $ $ =1.89=E_{cell}^{0}-(-0.28) $ $ E_{cell}^{0}=1.89-0.28=1.61 $ Volts.



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