SATHEE: Redox Reactions And Electrochemistry Ques 191

Redox Reactions And Electrochemistry Ques 191

Question: What will be the emf for the given cell $P t | H_{2} (P_{1}) | {H^{+}}_{(a q)} | | H_{2} (P_{2}) | P t$ [AIEEE 2002]

Options:

A) $\frac{R T}{f} \log \frac{P_{1}}{P_{2}}$

B) $\frac{R T}{2 f} \log \frac{P_{1}}{P_{2}}$

C) $\frac{R T}{f} \log \frac{P_{2}}{P_{1}}$

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

Anodic reaction : $H_{2} (P_{1}) \to 2 H^{+}$
Cathodic reaction : $2 H^{+} \to H_{2} (P_{2})$

$E_{c a t h o d e} = - \frac{R T}{2 F} \ln \frac{P_{2}}{{[H^{+}]}^{2}}$ ;

$E_{a n o d e} = - \frac{R T}{2 F} \ln \frac{{[H^{+}]}^{2}}{P_{1}}$

$E_{inf} = E_{a n o d e} + E_{c a t h o d e}$ $= - \frac{R T}{2 F} \ln \frac{{(H^{+})}^{2}}{P_{1}} - \frac{R T}{2 F} \ln \frac{P_{2}}{{(H^{+})}^{2}}$

$= - \frac{R T}{2 F} \ln \frac{P_{2}}{P_{1}} = \frac{R T}{2 F} \ln \frac{P_{1}}{P_{2}}$ .

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Redox Reactions And Electrochemistry Ques 191

Question: What will be the emf for the given cell Pt|H2(P1)|H+(aq)||H2(P2)|Pt [AIEEE 2002]

Options:

Answer:

Solution:

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Question: What will be the emf for the given cell $P t | H_{2} (P_{1}) | {H^{+}}_{(a q)} | | H_{2} (P_{2}) | P t$ [AIEEE 2002]