Redox Reactions And Electrochemistry Ques 177
Question: The $ E^{o} $ for half cells $ Fe/F{e^{2+}} $ and $ Cu/C{u^{2+}} $ are - 0.44 V and + 0.32 V respectively. Then [MP PMT 2003]
Options:
A) $ C{u^{2+}} $ oxidises $ Fe $
B) $ C{u^{2+}} $ oxidises $ F{e^{2+}} $
C) $ Cu $ oxidises $ F{e^{2+}} $
D) $ Cu $ reduces $ F{e^{2+}} $
Show Answer
Answer:
Correct Answer: A
Solution:
Fe is more electropositive than copper. Hence $ C{u^{2+}} $ can oxidise Fe.