SATHEE: Redox Reactions And Electrochemistry Ques 175

Redox Reactions And Electrochemistry Ques 175

Question: The emf of a Daniel cell at 298K is $E_{1}$ $Z n | \underset{(0.01 M)}{Z n S O_{4}}, | | \underset{(1.0 M)}{C u S O_{4}}, | C u$ when the concentration of $Z n S O_{4}$ is 1.0 M and that of $C u S O_{4}$ is 0.01 M, the emf changed to $E_{2}$ . What is the relationship between $E_{1}$ and $E_{2}$ [CBSE PMT 2003]

Options:

A) $E_{2} = 0 \neq E_{1}$

B) $E_{1} > E_{2}$

C) $E_{1} < E_{2}$

D) $E_{1} = E_{2}$

Show Answer

Answer:

Correct Answer: B

Solution:

$E_{1} = E_{o} - \frac{0.0591}{2} \log \frac{0.01}{1} = E_{o} + \frac{0.0591}{2} \times 2$ $E_{2} = E_{o} - \frac{0.0591}{2} \log \frac{100}{0.01} = E_{o} - \frac{0.0591}{2} \times 4$
$∴ E_{1} > E_{2}$ .

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Redox Reactions And Electrochemistry Ques 175

Question: The emf of a Daniel cell at 298K is E1 Zn|ZnSO4(0.01M),||CuSO4(1.0M),|Cu when the concentration of ZnSO4 is 1.0 M and that of CuSO4 is 0.01 M, the emf changed to E2 . What is the relationship between E1 and E2 [CBSE PMT 2003]

Options:

Answer:

Solution:

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