Redox Reactions And Electrochemistry Ques 119
Question: The conductivity of a saturated solution of $ BaSO_4 $ is $ 3.06\times {{10}^{-6}},oh{{m}^{-1}},c{{m}^{-1}} $ and its equivalent conductance is $ 1.53,oh{{m}^{-1}},c{{m}^{-1}},equivalen{{t}^{-1}} $ . The $ K_{sp} $ of the $ BaSO_4 $ will be [KCET 1996]
Options:
A) $ 4,\times {{10}^{-12}} $
B) $ 2.5\times {{10}^{-9}} $
C) $ 2.5\times {{10}^{-13}} $
D) $ 4\times {{10}^{-6}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \lambda m=\frac{1000,K}{S}=\frac{1000\times 3.06\times {{10}^{-6}}}{S}=1.53 $ $ S=2\times {{10}^{-3}}\frac{mol}{litre} $ $ {K_{sp(BaSO_4)}}=S^{2}={{(2\times {{10}^{-3}})}^{2}}=4\times {{10}^{-6}} $ .
