A) $ XeSiO_4+HF $
B) $ XeF_2+SiF_4 $
C) $ XeOF_4+SiF_4 $
D) $ XeO_3+SiF_2 $
Correct Answer: C
$ 2XeF_6+SiO_2\to SiF_4+2XeOF_4 $
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