[SCRA 1991]
A) $ H_2SO_4 $ (conc.)
B) $ H_2SO_4 $ (dil.)
C) $ H_2SO_4 $
D) $ H_2S_2O_7 $
Correct Answer: D
$ H_2SO_4+SO_3\to \underset{(oleum)}{\mathop{H_2S_2O_7}} $
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