[MNR 1984; MP PET/PMT 1998]
A) $ ZnSO_4 $
B) $ CuSO_4 $
C) $ {{(NH_4)}_2}SO_4 $
D) $ Na_2SO_4 $
Correct Answer: B
$ CuSO_4+2KI\to CuI_2+K_2SO_4 $ $ 2CuI_2\to \underset{\text{Cuprous iodide}}{\mathop{2CuI+I_2}} $
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