Equilibrium Question 885

Question: Taking $ Ba{{(OH)}_2} $ to be completely ionised. The pH of its 0.001 M solution is

Options:

A) 11.3

B) 2.7

C) 11

D) 3

Show Answer

Answer:

Correct Answer: A

Solution:

$ [O{H^{-}}]=2[Ba{{(OH)}_2}]=2\times .001=2\times {10^{-3}} $

$ pOH=-\log 2\times {10^{-3}},=2.7 $

$ pH=14-pOH=14-2.7=11.3 $



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक