Equilibrium Question 848

Question: The 0.001M solution of $ Mg{{(NO_3)}_2} $ is adjusted to pH 9, $ K _{sp} $ of $ Mg{{(OH)}_2} $ is $ 8.9\times {10^{-12}} $ . At this pH

Options:

A) $ Mg{{(OH)}_2} $ will be precipitated

B) $ Mg{{(OH)}_2} $ is not precipitated

C) $ Mg{{( OH )}_3} $ will be precipitated

D) $ Mg{{( OH )}_3} $ is not precipitated

Show Answer

Answer:

Correct Answer: B

Solution:

$ pH=9;[ {H^{+}} ]={10^{-9}};[ O{H^{-}} ]={10^{-5}}; $

$ [M{g^{2+}}]=1\times {10^{-3}};[M{g^{2+}}]{{[O{H^{-}}]}^{2}}=1\times {10^{-13}} $ given $ K _{sp} $ of $ Mg{{( OH )}_2}=8.9\times {10^{-12}} $ which is more than $ 1\times {10^{-13}} $ . Hence $ Mg{{(OH)}_2} $ will not precipitate



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक