Equilibrium Question 844
Question: The percentage hydrolysis of 0.15 M solution of ammonium acetate, $ K_{a} $ for $ CH_3COOH $ is $ 1.8\times {10^{-5}} $ and $ K_{b} $ for $ NH_3 $ is $ 1.8\times {10^{-5}} $
Options:
A) 0.55
B) 4.72
C) 9.38
D) 5.56
Show Answer
Answer:
Correct Answer: A
Solution:
$ \alpha =\sqrt{\frac{K_{w}}{K_{a}\times K_{b}}} $
$ =\sqrt{\frac{1\times {10^{-14}}}{1.8\times {10^{-5}}\times 1.8\times {10^{-5}}}}=0.55% $ %
