Equilibrium Question 824

Question: The dissociation constant of 0.1 M acetic acid solution is $ 1.8\times {10^{-5}} $ . If 1 L of this solution is mixed with 0.05 mole of $ HCl $ , what will be pH of mixture- $ [ log5=0.7 ] $

Options:

A) 1.3

B) 2.6

C) 1.9

D) 3.4

Show Answer

Answer:

Correct Answer: A

Solution:

The pH of mixture is due to the $ HCl $ only, because $ CH_3COOH $ is negligibly ionised due to common ion effect. Thus, $ [{H^{+}}]=0.05M=5\times {10^{-2}}M $

$ pH=-log( 5\times {10^{-2}} )=-[ log5+log{10^{-2}} ] $

$ pH=1.3 $



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