SATHEE: Equilibrium Question 814

Equilibrium Question 814

Question: The degree of dissociation of 0.1 M weak acid HA is 0.5%. If 2 mL of 1.0 M HA solution is diluted to 32 mL the degree of dissociation of acid and $H_{3} O^{+}$ ion concentration in the resulting solution will be respectively

Options:

A) 0.02 and $3.125 \times 10^{- 4}$

B) $1.25 \times 10^{- 3}$ and 0.02

C) 0.02 and $1.25 \times 10^{- 3}$

D) 0.02 and $8.0 \times 10^{- 12}$

Show Answer

Answer:

Correct Answer: C

Solution:

$α_{1} = 0.005 = \sqrt{K_{a} \times C_{1}}$ Molarity of diluted solution; $2 \times 1 = 32 \times M,$

$M = \frac{1}{16} (C_{2})$

$α_{2} = \sqrt{\frac{K_{a}}{C_{2}}} = 0.005 \sqrt{16} = 0.02$

$H_{3} \overset{+}{O}, = C_{2} α_{2} = \frac{0.02}{16} = 1.25 \times 10^{- 3} M$

पिछला

अगला

Equilibrium Question 814

Question: The degree of dissociation of 0.1 M weak acid HA is 0.5%. If 2 mL of 1.0 M HA solution is diluted to 32 mL the degree of dissociation of acid and $H_{3} O^{+}$ ion concentration in the resulting solution will be respectively

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Equilibrium Question 814

Question: The degree of dissociation of 0.1 M weak acid HA is 0.5%. If 2 mL of 1.0 M HA solution is diluted to 32 mL the degree of dissociation of acid and H3O+ ion concentration in the resulting solution will be respectively

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

Menu

Question: The degree of dissociation of 0.1 M weak acid HA is 0.5%. If 2 mL of 1.0 M HA solution is diluted to 32 mL the degree of dissociation of acid and $H_{3} O^{+}$ ion concentration in the resulting solution will be respectively