SATHEE: Equilibrium Question 809

Equilibrium Question 809

Question: Assuming that the buffer in the blood is $C O_{2} - H C O_{3}^{-}$ . Calculate the ratio of conjugate base to acid necessary to maintain blood at its proper pH of 7.4. $K_{1} (H_{2} C O_{3}) = 4.5 \times 10^{- 7}$

Options:

A) 11

B) 8

C) 6

D) 14

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Answer:

Correct Answer: A

Solution:

$C O_{2}$ with $H_{2} O$ forms $H_{2} C O_{3}$

$C O_{2} + H_{2} O \to H^{+} + H C O_{3}^{-}$

$K_{1} = \frac{[H^{+}] [H C O_{3}^{-}]}{[C O_{2}]} = 4.5 \times 10^{- 7}$ Again $p H = - \log [H^{+}] = 7.4$

$∴, [H^{+}] = 4.0 \times 10^{- 8}$

$∴, \frac{[H C O_{3}^{-}]}{[C O_{2}]} = \frac{4.5 \times 10^{- 7}}{4 \times 10^{- 8}} = 11$

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Equilibrium Question 809

Question: Assuming that the buffer in the blood is $C O_{2} - H C O_{3}^{-}$ . Calculate the ratio of conjugate base to acid necessary to maintain blood at its proper pH of 7.4. $K_{1} (H_{2} C O_{3}) = 4.5 \times 10^{- 7}$

Options:

Answer:

Solution:

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Equilibrium Question 809

Question: Assuming that the buffer in the blood is CO2−HCO3− . Calculate the ratio of conjugate base to acid necessary to maintain blood at its proper pH of 7.4. K1(H2CO3)=4.5×10−7

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: Assuming that the buffer in the blood is $C O_{2} - H C O_{3}^{-}$ . Calculate the ratio of conjugate base to acid necessary to maintain blood at its proper pH of 7.4. $K_{1} (H_{2} C O_{3}) = 4.5 \times 10^{- 7}$