Equilibrium Question 794
Question: A solution contains 10 mL 0.1 N $ NaOH $ and 10 mL 0.05 N $ H_2SO_4 $ , pH of this solution is:
Options:
A) less than 7
B) 7
C) zero
D) greater than 7
Show Answer
Answer:
Correct Answer: B
Solution:
Milliequivalents of $ NaOH=10\times 0.1=1 $ Milliequivalents of $ H_2SO_4=10\times 0.05=0.5 $
$ \underset{2,equ.}{\mathop{2NaOH}},+\underset{1,equ.}{\mathop{H_2SO_4}},\xrightarrow{{}}Na_2SO_4+H_2O $
$ \therefore $ 1 equivalent of $ NaOH $ reacts with 0.5 eq. of $ H_2SO_4 $ to give neutral $ ( pH=7 ) $ solution.
