Equilibrium Question 792

Question: A solution of 0.1MNaZ has pH=8.90. The Ka of HZ is

Options:

A) 6.3×1011

B) 6.3×1010

C) 1.6×105

D) 1.6×106

Show Answer

Answer:

Correct Answer: C

Solution:

NaZ is salt of WA/SB

pH=12(pKW+pKa+logC)

8.9×2=14+pKa+log0.1

17.8=14+pKa1

pKa=4.8,

Ka = Antilog (4.8)

=1.585×1051.6×105



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