A) pH of $ 1\times 10^{8}MHCl $ is 8
B) 96500 coulomb deposits 1 g equivalent of copper
C) Conjugate base of $ H_2P{O^{-}}_4 $ is $ HP{O^{2-}}_4 $ .
D) $ pH+pOH=14 $ for all aqueous solution
Correct Answer: A
$ pH $ of $ 1\times 10^{8}M $
$ HCl $ is $ \simeq $ 7 ( $ HCl $ is acid)
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