SATHEE: Equilibrium Question 732

Equilibrium Question 732

Question: The standard Gibbs energy change at 300 K for the reaction $2 A \to B + C$ is 2494.2J. At a given time, the composition of the reaction mixture is [A]= $\frac{1}{2}, [B] = 2, a n d, (C) = \frac{1}{2}$ . [R=8.314J/Kmol, e=2.718]

Options:

A) forward direction because $Q > K_{C}$

B) reverse direction because $Q > K_{C}$

C) forward direction because $Q < K_{C}$

D) reverse direction because $Q < K_{C}$

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Answer:

Correct Answer: B

Solution:

$Δ G = Δ G^{o} + R T$ In Q $= 249.2 + 8.314 \times 300$ In 4 =Positive $Δ G = R T$ In $\frac{Q}{K}$ Since, $Δ G$ is positive so Q>K, so reaction shifts in reverse direction.

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Equilibrium Question 732

Question: The standard Gibbs energy change at 300 K for the reaction $2 A \to B + C$ is 2494.2J. At a given time, the composition of the reaction mixture is [A]= $\frac{1}{2}, [B] = 2, a n d, (C) = \frac{1}{2}$ . [R=8.314J/Kmol, e=2.718]

Options:

Answer:

Solution:

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Equilibrium Question 732

Question: The standard Gibbs energy change at 300 K for the reaction 2A→B+C is 2494.2J. At a given time, the composition of the reaction mixture is [A]= 12,[B]=2,and,(C)=12 . [R=8.314J/Kmol, e=2.718]

Options:

Answer:

Solution:

इंजीनियरिंग की तैयारी

चिकित्सा तैयारी

एनसीईआरटी पुस्तकें और समाधान

महत्वपूर्ण संसाधन

अन्य संसाधन

पाठ्यक्रम

परीक्षा मंच

नमूना मॉक टेस्ट

सदस्यता

एनसीईआरटी व्यायाम वीडियो समाधान

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Question: The standard Gibbs energy change at 300 K for the reaction $2 A \to B + C$ is 2494.2J. At a given time, the composition of the reaction mixture is [A]= $\frac{1}{2}, [B] = 2, a n d, (C) = \frac{1}{2}$ . [R=8.314J/Kmol, e=2.718]