Equilibrium Question 664
Question: For the reaction : $ {H_{2(g)}}+C{O_{2(g)}} $ ⇌ $ C{O_{(g)}}+H_2{O_{(g)}} $ , if the initial concentration of $ [H_2]=[CO_2] $ and $ x $ moles/litre of hydrogen is consumed at equilibrium, the correct expression of $ K_{p} $ is [Orissa JEE 2005]
Options:
A) $ \frac{x^{2}}{{{(1-x)}^{2}}} $
B) $ \frac{{{(1+x)}^{2}}}{{{(1-x)}^{2}}} $
C) $ \frac{x^{2}}{{{(2+x)}^{2}}} $
D) $ \frac{x^{2}}{1-x^{2}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ {H_{2(g)}}+C{O_{2(g)}} $ ⇌ $ C{O_{(g)}}+H_2{O_{(l)}} $
Initial conc. | 1 | 1 | 0 | 0 |
At equili | (1- x) | (1 - x) | x | x |
$ K_{p}=\frac{p_{CO}.{p_{H_2O}}}{{p_{H_2}}.{p_{CO_2}}}=\frac{x.x}{(1-x)(1-x)}=\frac{x^{2}}{{{(1-x)}^{2}}} $