Equilibrium Question 660
Question: 2 mol of $ N_2 $ is mixed with 6 mol of $ H_2 $ in a closed vessel of one litre capacity. If 50% of $ N_2 $ is converted into $ NH_3 $ at equilibrium, the value of $ K_{c} $ for the reaction $ {N_{2(g)}}+3{H_{2(g)}} $ ⇌ $ 2N{H_{3(g)}} $ is [Kerala PMT 2004]
Options:
A) $ 4/27 $
B) $ 27/4 $
C) $ 1/27 $
D) 24
E) 9
Show Answer
Answer:
Correct Answer: A
Solution:
$ \underset{(a-x)}{\mathop{\overset{a}{\mathop{N_2}},}},+\underset{(b-3x)}{\mathop{\overset{b}{\mathop{3H_2}},}}, $ ⇌ $ \underset{(2x)}{\mathop{\overset{0}{\mathop{2NH_3}},}}, $ 50% Dissociation of $ N_2 $ take place so, At equilibrium $ \frac{2\times 50}{100}=1 $ ; value of $ x=1 $
$ K_{c}=\frac{{{[2]}^{2}}}{[1],{{[3]}^{3}}}=\frac{4}{27} $ so, $ K_{c}=\frac{4}{27} $
