SATHEE: Equilibrium Question 656

Equilibrium Question 656

Question: The equilibrium constant for the reaction $N_{2 (g)} + O_{2 (g)}$ ⇌ $2 N O_{(g)}$ at temperature T is $4 \times 10^{- 4}$ . The value of $K_{c}$ for the reaction $N O_{(g)}$ ⇌ $\frac{1}{2} N_{2 (g)} + \frac{1}{2} O_{2 (g)}$ at the same temperature is [AIEEE 2004]

Options:

A) $4 \times 10^{- 4}$

B) $50$

C) $2.5 \times 10^{2}$

D) 0.02

Show Answer

Answer:

Correct Answer: B

Solution:

$N_{2} (g) + O_{2} (g)$ ⇌ $2 N O (g)$

$K c = \frac{{[N O]}^{2}}{[N_{2}] [O_{2}]} = 4 \times 10^{- 4}$

$N O_{2}$ ⇌ $\frac{1}{2} N_{2} (g) + \frac{1}{2} O_{2} (g)$

${K^{'}}_{c} = \frac{{[N_{2}]}^{1 / 2} {[O_{2}]}^{1 / 2}}{[N O]} = \frac{1}{\sqrt{K c}} = \frac{1}{\sqrt{4 \times 10^{- 4}}}$

$= \frac{1}{2 \times 10^{- 2}} = \frac{100}{2} = 50$

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Equilibrium Question 656

Question: The equilibrium constant for the reaction N2(g)+O2(g) ⇌ 2NO(g) at temperature T is 4×10−4 . The value of Kc for the reaction NO(g) ⇌ 12N2(g)+12O2(g) at the same temperature is [AIEEE 2004]

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Question: The equilibrium constant for the reaction $N_{2 (g)} + O_{2 (g)}$ ⇌ $2 N O_{(g)}$ at temperature T is $4 \times 10^{- 4}$ . The value of $K_{c}$ for the reaction $N O_{(g)}$ ⇌ $\frac{1}{2} N_{2 (g)} + \frac{1}{2} O_{2 (g)}$ at the same temperature is [AIEEE 2004]