Equilibrium Question 627
Question: In the reaction $ A+2B $ ⇌ $ 2C $ , if 2 moles of $ A,3.0 $ moles of $ B $ and 2.0 moles of $ C $ are placed in a $ 2.0l $ flask and the equilibrium concentration of $ C $ is 0.5 mole/ $ l $ . The equilibrium constant $ (K_{c}) $ for the reaction is [KCET 1996]
Options:
A) 0.073
B) 0.147
C) 0.05
D) 0.026
Show Answer
Answer:
Correct Answer: C
Solution:
A + 2B ⇌ 2C Initial conc. 2 3 2 at eqm. 2.5 4 1 Molar $ \frac{2.5}{2}=1.25 $
$ \frac{4}{2}=2 $
$ \frac{1}{2}=0.5 $
$ K=\frac{{{[0.5]}^{2}}}{[1.25]\times {{[2]}^{2}}}=0.05 $
