Equilibrium Question 601

Question: For the system $ 3A+2B $ ⇌ $ C $ , the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]

Options:

A) $ \frac{[3A][2B]}{C} $

B) $ \frac{[C]}{[3A][2B]} $

C) $ \frac{{{[A]}^{3}}{{[B]}^{2}}}{[C]} $

D) $ \frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}} $

Show Answer

Answer:

Correct Answer: D

Solution:

Equilibrium constant for the reaction , 3A + 2B ⇌ C is K $ =\frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}} $ .



जेईई के लिए मॉक टेस्ट

एनसीईआरटी अध्याय वीडियो समाधान

दोहरा फलक