Equilibrium Question 601
Question: For the system $ 3A+2B $ ⇌ $ C $ , the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]
Options:
A) $ \frac{[3A][2B]}{C} $
B) $ \frac{[C]}{[3A][2B]} $
C) $ \frac{{{[A]}^{3}}{{[B]}^{2}}}{[C]} $
D) $ \frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}} $
Show Answer
Answer:
Correct Answer: D
Solution:
Equilibrium constant for the reaction , 3A + 2B ⇌ C is K $ =\frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}} $ .
