SATHEE: Equilibrium Question 601

Equilibrium Question 601

Question: For the system $3 A + 2 B$ ⇌ $C$ , the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]

Options:

A) $\frac{[3 A] [2 B]}{C}$

B) $\frac{[C]}{[3 A] [2 B]}$

C) $\frac{{[A]}^{3} {[B]}^{2}}{[C]}$

D) $\frac{[C]}{{[A]}^{3} {[B]}^{2}}$

Show Answer

Answer:

Correct Answer: D

Solution:

Equilibrium constant for the reaction , 3A + 2B ⇌ C is K $= \frac{[C]}{{[A]}^{3} {[B]}^{2}}$ .

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Equilibrium Question 601

Question: For the system 3A+2B ⇌ C , the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]

Options:

Answer:

Solution:

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Question: For the system $3 A + 2 B$ ⇌ $C$ , the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]