Equilibrium Question 585
Question: For the reaction, $ PC{l_{3(g)}} $ + $ C{l_{2(g)}} $ ⇌ $ PC{l_{5(g)}} $ , the value of $ K_{c} $ at 250°C is 26. The value of $ K_{p} $ at this temperature will be [UPSEAT 1999, 2000, 02]
Options:
A) 0.61
B) 0.57
C) 0.83
D) 0.46
Show Answer
Answer:
Correct Answer: A
Solution:
$ K_{p}=K_{c}{{[RT]}^{\Delta n}};\Delta n=-1,K_{c}=26 $
$ R=0.0812,,T=250+273=523K $
$ K_{p}=26{{[0.0812\times 523]}^{-1}}=0.605\approx 0.61 $
