Equilibrium Question 573
Question: At 490°C, the equilibrium constant for the synthesis of HI is 50, the value of K for the dissociation of HI will be [KCET 2000]
Options:
A) 20.0
B) 2.0
C) 0.2
D) 0.02
Show Answer
Answer:
Correct Answer: D
Solution:
K for dissociation of HI =- $ H_2+I_2 $ ⇌ 2HI $ K_{a}=50 $ , $ K_{b}=\frac{1}{50}=0.02 $
