SATHEE: Equilibrium Question 565

Equilibrium Question 565

Options:

A) $K = K^{'}$

B) $K^{'} = \sqrt{K}$

C) $K = \sqrt{K^{'}}$

D) $K \times K^{'} = 1$

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Answer:

Correct Answer: B

Solution:

$K^{'} = K^{n};$ Hence $n = \frac{1}{2}$

$∴ K^{'} = K^{1 / 2} = \sqrt{K}$

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Equilibrium Question 565

Question: The equilibrium constant for the reversible reaction, N2+3H2 ⇌ 2NH3 is K and for the reaction 12N2+32H2 ⇌ NH3 the equilibrium constant is K′ . K and K′ will be related as [MP PET 1997]

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Question: The equilibrium constant for the reversible reaction, $N_{2} + 3 H_{2}$ ⇌ $2 N H_{3}$ is $K$ and for the reaction $\frac{1}{2} N_{2} + \frac{3}{2} H_{2}$ ⇌ $N H_{3}$ the equilibrium constant is $K^{'}$ . $K$ and $K^{'}$ will be related as [MP PET 1997]