Equilibrium Question 564
Question: For reaction 2NOCl(g) ⇌ $ 2NO(g)+Cl_2(g) $ , $ K_{C} $ at 427°C is $ 3\times {10^{-6}}L\ mo{l^{-1}} $ . The value of $ K_{P} $ is nearly [AIIMS 2005]
Options:
A) $ 7.50\times {10^{-5}} $
B) $ 2.50\times {10^{-5}} $
C) $ 2.50\times {10^{-4}} $
D) $ 1.75\times {10^{-4}} $
Show Answer
Answer:
Correct Answer: D
Solution:
2NOCl(g) = 2NO(g) + Cl2(g) Kp = KC (RT)∆n Kp = 3 ´ 10-6 (0.0821 ´ 700) = 172.41 ´ 10-6 = 1.72 ´ 10-4
