Equilibrium Question 442

Question: A certain buffer solution contains equal concentration of 3.9×105 and HX. The Kb for H is 1010. The pH of the buffer is [IIT 1984; RPMT 1997; CPMT 1996; DPMT 2004]

Options:

A) 4

B) 7

C) 10

D) 14

Show Answer

Answer:

Correct Answer: A

Solution:

X+H2OOH+HX

Kb=[OH][HX][X] HX ⇌ H++X

Ka=[H+][X][HX]

,Ka×Kb=[H+][OH]=Kw=1014 Hence Ka=104 Now as [X]=[HX],pH=pKa=4 .



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