SATHEE: Equilibrium Question 432

Equilibrium Question 432

Question: $50 m l$ water is added to a $50 m l$ solution of $B a {(O H)}_{2}$ of strength $0.01 M .$ The $p H$ value of the resulting solution will be [MP PMT 1999]

Options:

A) 8

B) 10

C) 12

D) 6

Show Answer

Answer:

Correct Answer: C

Solution:

0.01 M $B a {(O H)}_{2} = 0.02 N B a {(O H)}_{2}$

$N_{1} V_{1} = N_{2} V_{2}$

$[0.02 N] \times [50 m l] = N_{2} \times 100 m l$

$N_{2} = \frac{0.02 \times 50}{100}$

$= 10^{- 2} N$ ; $[O H^{-}] = 10^{- 2}$ N $p O H = 2$ or $p H = 12$

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Equilibrium Question 432

Question: 50ml water is added to a 50ml solution of Ba(OH)2 of strength 0.01M. The pH value of the resulting solution will be [MP PMT 1999]

Options:

Answer:

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Question: $50 m l$ water is added to a $50 m l$ solution of $B a {(O H)}_{2}$ of strength $0.01 M .$ The $p H$ value of the resulting solution will be [MP PMT 1999]