Equilibrium Question 401

Question: pH of a solution of $ 10,ml $ . 1N sodium acetate and $ 50,ml $ 2N acetic acid $ (K_{a}=1.8\times {10^{-5}}), $ is approximately [MP PMT 2003]

Options:

A) 4

B) 5

C) 6

D) 7

Show Answer

Answer:

Correct Answer: A

Solution:

$ pH=pK_{a}+log\frac{[\text{ Salt }]}{[\text{ Acid }]} $

$ pH=-\log ,(1.8\times {10^{-5}})+\log \frac{[10]}{[100]} $

$ =-\log 1.8+5+\log {10^{-1}} $

$ =-\ 0.2553+5-1=3.7447,or=4 $



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