Equilibrium Question 392
Question: $ pH $ values of $ HCl $ and $ NaOH $ solutions each of strength $ \frac{N}{100} $ will be respectively [MP PMT 1999]
Options:
A) 2 and 2
B) 2 and 12
C) 12 and 2
D) 2 and 10
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{N}{100}=0.01,N,HCl $ ; $ [{H^{+}}]={10^{-2}} $ M ; $ pH=2 $
$ [OH]={10^{-2}} $ M for NaOH $ pH+pOH=14 $ ; $ pH=14-2 $ ; $ pH=12 $
