SATHEE: Equilibrium Question 384

Equilibrium Question 384

Question: What is the correct relationship between the $p H s$ of isomolar solutions of sodium oxide $(p H_{1})$ , sodium sulphide $(p H_{2}),$ sodium selenide $(p H_{3})$ and sodium telluride $(p H_{4})$ - [CBSE PMT 2005]

Options:

A) $p H_{1} > p H_{2} = p H_{3} > p H_{4}$

B) $p H_{1} < p H_{2} < p H_{3} < p H_{4}$

C) $p H_{1} < p H_{2} < p H_{3} = p H_{4}$

D) $p H_{1} > p H_{2} > p H_{3} > p H_{4}$

Show Answer

Answer:

Correct Answer: D

Solution:

Order of acidic strength is $H_{2} T e > H_{2} S e > H_{2} S > H_{2} O$

$N a_{2} O$ is a salt of NaOH $+ H_{2} O$ and $H_{2} O$ is least acidic among given acids hence $p H$ in this case will be ${max}^{m}$ .

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Equilibrium Question 384

Question: What is the correct relationship between the pHs of isomolar solutions of sodium oxide (pH1) , sodium sulphide (pH2), sodium selenide (pH3) and sodium telluride (pH4) - [CBSE PMT 2005]

Options:

Answer:

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Question: What is the correct relationship between the $p H s$ of isomolar solutions of sodium oxide $(p H_{1})$ , sodium sulphide $(p H_{2}),$ sodium selenide $(p H_{3})$ and sodium telluride $(p H_{4})$ - [CBSE PMT 2005]