Equilibrium Question 310
Question: At 298K a 0.1 M $ CH_3COOH $ solution is 1.34% ionized. The ionization constant $ K_{a} $ for acetic acid will be [AMU 2002; AFMC 2005]
Options:
A) $ 1.82\times {10^{-5}} $
B) $ 18.2\times {10^{-5}} $
C) $ 0.182\times {10^{-5}} $
D) None of these
Show Answer
Answer:
Correct Answer: A
Solution:
$ K=c{{\alpha }^{2}}=0.1\times {{( \frac{1.34}{100} )}^{2}}=1.8\times {10^{-5}} $ .
