Equilibrium Question 298
Question: $ pK_{a} $ value for acetic acid at the experimental temperature is 5. The percentage hydrolysis of $ 0.1M $ sodium acetate solution will be
Options:
A) $ 1\times {10^{-4}} $
B) $ 1\times {10^{-2}} $
C) $ 1\times {10^{-3}} $
D) $ 1\times {10^{-3}} $
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Answer:
Correct Answer: B
Solution:
$ pKa=5 $ , so $ Ka=1\times {10^{-5}} $
$ \alpha =\sqrt{\frac{Ka}{C}}=\sqrt{\frac{1\times {10^{-5}}}{0.1}}=1\times {10^{-2}} $