Equilibrium Question 288

Question: In the equilibrium A+H2OHA+OH

(Ka=1.0×105) . The degree of hydrolysis of 0.001 M solution of the salt is [AMU 1999]

Options:

A) 103

B) 104

C) 105

D) 106

Show Answer

Answer:

Correct Answer: A

Solution:

Ka=1.0×105

Kh=hydrolysisconstant

Kh=KwKa=1014105=109 degree of hydrolysis (h ) = KhC

=1090.001 = 106 = 103 ; h=103



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