Equilibrium Question 288

Question: In the equilibrium $ {A^{-}}+H_2O $ ⇌ $ HA+O{H^{-}} $

$ (K_{a}=1.0\times {10^{-5}}) $ . The degree of hydrolysis of 0.001 M solution of the salt is [AMU 1999]

Options:

A) $ {10^{-3}} $

B) $ {10^{-4}} $

C) $ {10^{-5}} $

D) $ {10^{-6}} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ K_{a}=1.0\times {10^{-5}} $

$ K_{h}=hydrolysisconstant $

$ K_{h}=\frac{K_{w}}{K_{a}}=\frac{{10^{-14}}}{{10^{-5}}}={10^{-9}} $ degree of hydrolysis (h ) = $ \sqrt{\frac{K_{h}}{C}} $

$ =\sqrt{\frac{{10^{-9}}}{0.001}} $ = $ \sqrt{{10^{-6}}} $ = $ {10^{-3}} $ ; $ h={10^{-3}} $



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