Equilibrium Question 258
Question: The partial pressures of $ CH_3OH,,CO $ and $ H_2 $ in the equilibrium mixture for the reaction $ CO+2H_2 $ ⇌ $ CH _3OH $ at 427°C are 2.0, 1.0 and 0.1 atm respectively. The value of $ K _{P} $ for the decomposition of $ CH_3OH $ to CO and $ H_2 $ is [Roorkee 1999]
Options:
A) $ 1\times 10^{2} $ atm
B) $ 2\times 10^{2}at{m^{-1}} $
C) $ 50atm^{2} $
D) $ 5\times {10^{-3}}atm^{2} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ CH_3OH\to CO+2H_2 $
$ \frac{{{[H_2]}^{2}}[CO]}{[CH_3OH]}=\frac{0.1\times 0.1\times 1}{2}=\frac{0.01}{2}=\frac{10\times {10^{-3}}}{2} $
$ =5\times {10^{-3}} $ .
