Equilibrium Question 248
Question: The solubility of $ Sb_2S_3 $ in water is $ 1.0\times {10^{-5}} $ mol / litre at 298 K. What will be its solubility product [CPMT 2004]
Options:
A) $ 108\times {10^{-25}} $
B) $ 1.0\times {10^{-25}} $
C) $ 144\times {10^{-25}} $
D) $ 126\times {10^{-24}} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ Sb_2S_3\ \to \ \underset{2x,}{\mathop{2S{b^{+2}}}},+\underset{3x}{\mathop{3{S^{–}}}}, $ ; $ K _{sp}={{(2x)}^{2}}.{{(3x)}^{3}} $
$ K _{sp}=108x^{5} $ ; $ K _{sp}=108\times {{(1\times {10^{-5}})}^{5}} $
$ =108\times {10^{-25}} $ .
