Equilibrium Question 225
Question: Solubility of $ MX_2 $ type electrolyte is $ 0.5\times {10^{-4}}mole/litre $ . The value of $ K _{sp} $ of the electrolyte is [CBSE PMT 2002]
Options:
A) $ 5\times {10^{-13}} $
B) $ 25\times {10^{-10}} $
C) $ 1.25\times {10^{-13}} $
D) $ 5\times 10^{12} $
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Answer:
Correct Answer: A
Solution:
$ MX_2 $ ⇌ $ \underset{(S)}{\mathop{{M^{2+}}}},+,\underset{{{(2S)}^{2}}}{\mathop{2{X^{-}}}}, $ ; $ 4S^{3}=4\times {{(0.5\times {10^{-4}})}^{3}} $
$ =5\times {10^{-13}} $
