Equilibrium Question 207
Question: The solubility of $ CaCO_3 $ in water is $ 3.05\times {10^{-4}}moles/litre. $ Its solubility product will be [MP PMT 1997]
Options:
A) $ 3.05\times {10^{-4}} $
B) 10
C) $ 6.1\times {10^{-4}} $
D) $ 9.3\times {10^{-8}} $
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Answer:
Correct Answer: D
Solution:
$ \underset{S}{\mathop{CaCO_3}}, $ ⇌ $ \underset{S}{\mathop{C{a^{++}}}},+\underset{S}{\mathop{CO_3^{-,-}}}, $ Solubility product of $ CaCO_3 $
$ K _{sp}=S^{2} $ ; $ S=\sqrt{K _{sp}} $ It is a binary electrolyte. $ S^{2}=K _{sp} $ ; $ {{(3.05\times {10^{-4}})}^{2}}=K _{sp} $ ; $ K _{sp}=9.3\times {10^{-8}} $