Equilibrium Question 193

Question: The solubility product of $ 1\times {10^{-5}} $ is $ 1.44\times {10^{-4}} $ at $ 100^{o}C $ . The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]

Options:

A) $ 0.72\times {10^{-4}},M $

B) $ 1.20\times {10^{-2}},M $

C) $ 80^{o}C, $

D) $ 0.5,M,HCOOH, $

Show Answer

Answer:

Correct Answer: B

Solution:

AgCl ⇌ $ [A{g^{+}}][C{l^{-}}] $ ; $ K _{sp}=S\times S $ ; $ K _{sp}=S^{2} $

$ S=\sqrt{K _{sp}} $

$ =\sqrt{1.44\times {10^{-4}}} $

$ =1.20\times {10^{-2}} $ M.



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