SATHEE: Equilibrium Question 193

Equilibrium Question 193

Question: The solubility product of $1 \times 10^{- 5}$ is $1.44 \times 10^{- 4}$ at $100^{o} C$ . The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]

Options:

A) $0.72 \times 10^{- 4}, M$

B) $1.20 \times 10^{- 2}, M$

C) $80^{o} C,$

D) $0.5, M, H C O O H,$

Show Answer

Answer:

Correct Answer: B

Solution:

AgCl ⇌ $[A g^{+}] [C l^{-}]$ ; $K_{s p} = S \times S$ ; $K_{s p} = S^{2}$

$S = \sqrt{K_{s p}}$

$= \sqrt{1.44 \times 10^{- 4}}$

$= 1.20 \times 10^{- 2}$ M.

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Equilibrium Question 193

Question: The solubility product of 1×10−5 is 1.44×10−4 at 100oC . The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]

Options:

Answer:

Solution:

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Question: The solubility product of $1 \times 10^{- 5}$ is $1.44 \times 10^{- 4}$ at $100^{o} C$ . The solubility of silver chloride in boiling water may be [MP PMT 1994; Bihar MEE 1998]