SATHEE: Equilibrium Question 191

Equilibrium Question 191

Question: At $20^{o} C,$ the $A g^{+}$ ion concentration in a saturated solution of $A g_{2} C r O_{4}$ is $1.5 \times 10^{- 4}, m o l e / l i t r e .$ At $20^{o} C,$ the solubility product of $A g_{2} C r O_{4}$ would be [MP PET 1997; MP PMT 1999]

Options:

A) $3.3750 \times 10^{- 12}$

B) $1.6875 \times 10^{- 10}$

C) $1.6875 \times 10^{- 12}$

D) $1.6875 \times 10^{- 11}$

Show Answer

Answer:

Correct Answer: C

Solution:

$A g C r O_{4}$ ⇌ $\underset{{(2 S)}^{2}}{2 A g^{+}}, + \underset{S,}{C r O_{4}^{-}},$

$K_{s p} = 4 S^{3}$ given $2 S = 1.5 \times 10^{- 4}$

$∴, K_{s p} = {(2 S)}^{2} \times S$

$= {(1.5 \times 10^{- 4})}^{2} \times (\frac{1.5 \times 10^{- 4}}{2})$

$= 1.6875 \times 10^{- 12}$

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Equilibrium Question 191

Question: At 20oC, the Ag+ ion concentration in a saturated solution of Ag2CrO4 is 1.5×10−4,mole/litre. At 20oC, the solubility product of Ag2CrO4 would be [MP PET 1997; MP PMT 1999]

Options:

Answer:

Solution:

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Question: At $20^{o} C,$ the $A g^{+}$ ion concentration in a saturated solution of $A g_{2} C r O_{4}$ is $1.5 \times 10^{- 4}, m o l e / l i t r e .$ At $20^{o} C,$ the solubility product of $A g_{2} C r O_{4}$ would be [MP PET 1997; MP PMT 1999]