Equilibrium Question 16

Question: In the equilibrium $ CH_3COOH+HF $ ⇄ $ CH_3COOH_2^{+}+{F^{-}} $ [BHU 1987]

Options:

A) $ {F^{-}} $ is the conjugate acid of $ CH_3COOH $

B) $ {F^{-}} $ is the conjugate base of $ HF $

C) $ CH_3COOH $ is the conjugate acid of $ CH_3COOH_2^{+} $

D) $ CH_3COOH_2^{+} $ is the conjugate base of $ CH_3COOH $

Show Answer

Answer:

Correct Answer: B

Solution:

$ CH_3COOH+HF $ ⇌ $ CH_3COOH_2^{+}+{F^{-}} $ . $ HF $ gives $ {H^{+}} $ to the $ CH_3COOH $ . So it is a conjugate base of HF.



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