Equilibrium Question 158

Question: Solubility product of a sulphide MS is $ 3\times {10^{-25}} $ and that of another sulphide NS is $ 4\times {10^{-40}} $ . In ammoniacal solution [NCERT 1981]

Options:

A) Only NS gets precipitated

B) Only MS gets precipitated

C) No sulphide precipitates

D) Both sulphides precipitate

Show Answer

Answer:

Correct Answer: D

Solution:

The concentration of $ {S^{2-}} $ ions in group II is lowered by maintaining acidic medium in the presence of $ NH_4Cl $ . The ionization of $ H_2S $ is supressed due to common ion effect. So the ionic product is less than solubility product.



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