Equilibrium Question 157
Question: The solubility of $ CaF_2 $ is $ 2\times {10^{-4}},moles/litre. $ Its solubilily product $ (K _{sp}) $ is [NCERT 1981; BHU 1983, 86; MP PET 1992; CBSE PMT 1999]
Options:
A) $ 2.0\times {10^{-4}} $
B) $ 4.0\times {10^{-3}} $
C) $ 8.0\times {10^{-12}} $
D) $ 3.2\times {10^{-11}} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ K _{sp} $ for $ CaF_2=4s^{3} $
$ =4\times {{[2\times {10^{-4}}]}^{3}}=3.2\times {10^{-11}} $ .
