A) $ SO_4^{2-} $
B) $ H_2SO_4 $
C) $ H_3SO_4^{+} $
D) None of these
Correct Answer: A
$ \underset{\text{Conjugate acid}}{\mathop{HSO_4^{-}}},\to {H^{+}}+\underset{\text{Conjugate base}}{\mathop{SO_4^{2-}}}, $
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