Equilibrium Question 108
Question: The conjugate base in the following reaction $ H_2SO_4+H_2O $ ⇄ $ H_3{O^{+}}+HSO_4^{-} $ [DCE 1999]
Options:
A) $ H_2O $
B) $ HSO_4^{-} $
C) $ H_3{O^{+}} $
D) $ SO_2 $
Show Answer
Answer:
Correct Answer: B
Solution:
Conjugate acid base pair differ by a single proton and base is one which accept proton,acid is which donates proton.
So conjugate base of the acid is one formed after the donation of proton by the acid.
So the conjugate base of $H_2SO_4$ is $HSO^− _4.$
